Quiz 37

Anonymous
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description:

Jumping into a block and bypassing a declaration with an initialization is ill-formed. In this example there are cases which would bypass the declaration and initialization of block scope x declaration.

#include <iostream>
int main()
{
int x = 3;
switch(x)
{
case 0:
int x = 1;
std::cout << x << std::endl;
break;
case 3:
std::cout << x << std::endl;
break;
default:
x = 2;
std::cout << x << std::endl;
}
return 0;
}
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